4y^2+2=y

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Solution for 4y^2+2=y equation: 



4y^2+2=y

We move all terms to the left:

4y^2+2-(y)=0

We add all the numbers together, and all the variables

4y^2-1y+2=0

a = 4; b = -1; c = +2;
Δ = b2-4ac
Δ = -12-4·4·2
Δ = -31
Delta is less than zero, so there is no solution for the equation

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